Тип 2 № 10236

Сила тяготения: $$F = G \frac{Mm}{R^2}$$ $$\frac{F_1}{F_2} = \frac{m_1}{m_2} \cdot \frac{R_2^2}{R_1^2}$$ $$\frac{F_1}{F_2} = \frac{1}{4} \cdot \left(\frac{R_2}{R_1}\right)^2$$ $$\frac{R_1}{R_2} = 2{,}5 \implies \frac{R_2}{R_1} = 0{,}4$$ $$\frac{F_1}{F_2} = \frac{1}{4} \cdot (0{,}4)^2 = \frac{1}{4} \cdot 0{,}16 = 0{,}04$$